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Question

Using suitable identities, evaluate:
1.05 x 9.5

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Solution

1.5×0.5
=(1+0.5)(10.5)
Using suitable identity (x+a)(xb)=x2+(a+b)x+ab
where x=1,a=0.5,b=0.5
=12+(0.50.5)×1+0.5×0.5
=1+00.25=0.75

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