Using suitable identities- evalute 497 - 505-

The correct option is C 250985497 × 505 = (500 3) (500+5) =500^2 + ( 3+5) × 500 + ( 3) (5) [using (x+a)(x+b)=x^2+(a+b)x+ab] =250000 + 1000 15 =250985 ...

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Standard VII

Mathematics

(x + a)(x +b)= x^2 + x(a+ b) + ab

Using suitabl...

Question

Using suitable identities, evaluate $497 \times 505$ .

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250985

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Solution

The correct option is C 250985
We have, $497 \times 505$
$= (500 - 3) (500 + 5)$ [ $∵ 497 = 500 - 3,$ and $505 = 500 + 3$ ]
$= 500^{2} + (- 3 + 5) \times 500 + (- 3) (5)$ [Using $(x + a) (x + b) = x^{2} + (a + b) x + a b]$
$= 250000 + 1000 - 15$
$= 250985$

Suggest Corrections

Using suitable identities, evaluate 497×505.

The correct option is C 250985We have, 497×505 =(500−3)(500+5) [∵497=500−3, and 505=500+3] =5002+(−3+5)×500+(−3)(5) [Using (x+a)(x+b)=x2+(a+b)x+ab] =250000+1000−15 =250985

Using suitable identities, evaluate $497 \times 505$ .

The correct option is C 250985
We have, $497 \times 505$
$= (500 - 3) (500 + 5)$ [ $∵ 497 = 500 - 3,$ and $505 = 500 + 3$ ]
$= 500^{2} + (- 3 + 5) \times 500 + (- 3) (5)$ [Using $(x + a) (x + b) = x^{2} + (a + b) x + a b]$
$= 250000 + 1000 - 15$
$= 250985$