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Question
Using suitable identities, find the value of \(102^3\).
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Solution
Using the identity,
\((a+b)^3 = a^3+b^3+3ab(a+b)\),
\(\Rightarrow\) \(102^3\) \(=(100+2)^3\)
\(=100^3+ 2^3 +3×100×2(100+2)\)
\(=1000000+8+61200\)
\(=1061208\)
\((a+b)^3 = a^3+b^3+3ab(a+b)\),
\(\Rightarrow\) \(102^3\) \(=(100+2)^3\)
\(=100^3+ 2^3 +3×100×2(100+2)\)
\(=1000000+8+61200\)
\(=1061208\)
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