Using suitable identity- evaluate 136 - 107

The given expression is 136×107=(100+36)(100+7) nbsp; nbsp; Expanding using the identity (x+a)(x+b)= nbsp;x^2+(a+b)x+ab (100+36)(100+7) nbsp; =100^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Algebraic Identity: (x + a)(x + b) = x^2 + (a + b)x + ab

Using suitabl...

Question

Using suitable identity, evaluate $136 \times 107$
14552

Open in App

Solution

The correct option is A 14552
The given expression is 136×107=(100+36)(100+7)

Expanding using the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$

(100+36)(100+7)

= $100^{2} + (36 + 7) \times 100 + 36 \times 7$

= 10000 + 4300 + 252

= 14552

Suggest Corrections

Similar questions

Q. Using suitable identity, evaluate

52 \times 53.

136 \times 107

= (using identities)

Q. Evaluate (99)³ by using suitable identity.

Evaluate $136 \times 107$ .

Q. Evaluate the following using the suitable identity.
(i)

99^{3}

(ii)

1001^{2}

(iii)

105^{3}

(iv)

105 \times 108

(v)

91 \times 106

(vi)

107^{3}

Join BYJU'S Learning Program

Using suitable identity, evaluate 136×107 14552

The correct option is A 14552The given expression is 136×107=(100+36)(100+7) Expanding using the identity (x+a)(x+b)=x2+(a+b)x+ab (100+36)(100+7) =1002+(36+7)×100+36×7 = 10000 + 4300 + 252 = 14552

Using suitable identity, evaluate $136 \times 107$
14552

The correct option is A 14552
The given expression is 136×107=(100+36)(100+7)

Expanding using the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$

(100+36)(100+7)

= $100^{2} + (36 + 7) \times 100 + 36 \times 7$

= 10000 + 4300 + 252

= 14552