Using suitable identity- evaluate 136 - 107

The correct option is A 14552The given expression is 136×107=(100+36)(100+7) nbsp; nbsp; Expanding using the identity (x+a)(x+b)= nbsp;x^2+(a+b)x+ab (100+ ...

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Standard VI

Mathematics

Algebraic Identities

Using suitabl...

Question

Using suitable identity, evaluate $136 \times 107$
14552

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Solution

The correct option is A 14552
The given expression is 136×107=(100+36)(100+7)

Expanding using the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$

(100+36)(100+7)

= $100^{2} + (36 + 7) \times 100 + 36 \times 7$

= 10000 + 4300 + 252

= 14552

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Using suitable identity, evaluate 136×107 14552

The correct option is A 14552The given expression is 136×107=(100+36)(100+7) Expanding using the identity (x+a)(x+b)=x2+(a+b)x+ab (100+36)(100+7) =1002+(36+7)×100+36×7 = 10000 + 4300 + 252 = 14552

Using suitable identity, evaluate $136 \times 107$
14552

The correct option is A 14552
The given expression is 136×107=(100+36)(100+7)

Expanding using the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$

(100+36)(100+7)

= $100^{2} + (36 + 7) \times 100 + 36 \times 7$

= 10000 + 4300 + 252

= 14552