Using suitable identity expand ${(1 + x)}^{3}$

Open in App

Solution

${(1 + x)}^{3}$

Using ${(a + b)}^{3} = a^{3} + b^{3} + 3 a b (a + b)$

where $a = 1, b = x$

${(1 + x)}^{3} = 1^{3} + x^{3} + 3 \times 1 \times x (1 + x)$

$= 1 + x^{3} + 3 x + 3 x^{2}$

$= x^{3} + 3 x^{2} + 3 x + 1$

Suggest Corrections

Similar questions

{(\frac{1}{4} a - \frac{1}{2} b + 1)}^{2}

108 \times 105

{(y^{4} + {4 y}^{2} + 1)}^{2}

{(x - \frac{2}{3} y)}^{3}

{(99)}^{2}

Join BYJU'S Learning Program