wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Using suitable identity, find the value of (61)3

Open in App
Solution

(61)3=(60+1)3

Apply: (a+b)3=a3+b3+3ab(a+b)

(60+1)3=(60)3+(1)3+3×60×1(60+1)

=216000+1+180(61)

=216001+10980

=226981

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Polynomial and Its General Form
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon