Using suitable identity find the value of $98^{2}$

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Solution

$C o n c e p t I n v o l v e d - ------------------ -$ :
$(m - n)^{2} = (m - n) \times (m - n)$
$= m \times (m - n) - n \times (m - n)$
$= (m^{2} - m n) + (- m n + n^{2})$
$= m^{2} - 2 m n + n^{2}$

$M e t h o d - ------- -$ :
$(98)^{2} = (100 - 2)^{2} = (100 - 2) \times (100 - 2)$
$= 100 \times (100 - 2) - 2 \times (100 - 2)$
$= (100^{2} - 100 \cdot 2) + (- 100 \cdot 2 + 2^{2})$
$= 100^{2} - 2 \cdot 100 \cdot 2 + 2^{2}$
$= 10000 - 400 + 4$
$= 9604$

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