Using suitable identity, find the values of 104×105.
10920
10900
10290
10090
104×105=(100+4)(100+5)
Using the identity (x+a)(x+b)=x2+(a+b)x+ab
=1002+(4+5)100+4×5
=10000+400+500+20
=10000+900+20
=10920
Question 86 (x)
Using suitable identities, evaluate the following:
104×97
18. Find the value of m if 10m - 4 = 102 × 104 using a suitable identity.