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Question

Using suitable identity, find the values of 104×105.


A

10920

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B

10900

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C

10290

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D

10090

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Solution

The correct option is A

10920


104×105=(100+4)(100+5)

Using the identity (x+a)(x+b)=x2+(a+b)x+ab

=1002+(4+5)100+4×5

=10000+400+500+20

=10000+900+20

=10920


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