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Question

Using suitable identity solve (0.99)raised to the power 2.

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Solution

(0.99)² = ( 1 - 0.01)²

= (1)² + (0.01)² - 2 × 1 × 0.01
[ (a - b)²= a² + b² - 2ab]

= 1 + 0.0001 - 0.02

= 1.0001 - 0.02 = 0.9801


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Algebraic Identity: (a + b)^2 = a^2 + b^2 + 2ab
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