Question

Using suitable rearrangement and find the sum,
$-5+\frac{7}{10}+(-3)+\frac{3}{7}+\left(\frac{-4}{5}\right)+\frac{5}{14}$

Answer 1

$-5+\frac{7}{10}+(-3)+\frac{3}{7}+(\frac{-4}{5})+\frac{5}{14}=-5-3+\frac{7-8}{10}+\frac{6+5}{14}=2-\frac{1}{10}+\frac{11}{14}=\frac{140-7+55}{70}=\frac{188}{70}=\frac{94}{35}$