Question

Using suitable rearrangement, find the sum.
$\frac{4}{7}+\left(\frac{-4}{9}\right)+\frac{3}{7}+\left(\frac{-13}{9}\right)$

Answer 1

Here,

$\Rightarrow \frac{4}{7}+\left(\frac{-4}{9}\right)+\frac{3}{7}+\left(\frac{-13}{9}\right)$

$=\frac{4}{7}+\frac{3}{7}+\left(\frac{-4}{9}\right)+\left(\frac{-13}{9}\right)$ [Using commutative property]

$=\frac{7}{7}-\frac{17}{9}$

$=1-\frac{17}{9}$

$=\frac{9-17}{9}$

$=\frac{-8}{9}$