Using tanh x - e x - e -x e x - e -x and sech x - 2 e x - e -x find the value of sech 2 x -tanh 2 x

sech^2x+tanh^2x=(4(e^x+e^ x)^2)+((e^x e^ x)^2(e^x+e^ x)^2) #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #16 ...

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Theorems on Integration

Using tanh ...

Question

Using $tanh x = \frac{e^{x} - e^{- x}}{e^{x} + e^{- x}}$ and $sech x = \frac{2}{e^{x} + e^{- x}}$ find the value of
${sech}^{2} x + {tanh}^{2} x$

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Similar questions

tan h x = \frac{sin h x}{cos h x}

tan h x

e^{x}

e^{- x}

If $t a n θ + s e c θ = e^{x}$ , then $c o s θ$ equals

\int \frac{e^{x} - e^{- x}}{e^{x} + e^{- x}}

\int {(\frac{e^{x} + e^{- x}}{e^{x} - e^{- x}})}^{2} d x

y + \sqrt{1 + y^{2}} = e^{x},

y

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