Question

Using the antilog table given below, find out the antilog of $1.0427$.

• A. $1.104$
• B. $11.02$
• C. $11.04$
• D. $1.102$

Answer 1

The correct option is C $11.04$

We have to find the antilog of $1.0427$.

$\Rightarrow {10}^{1.0427}$

$\Rightarrow {10}^1{.10}^{0.0427}$

Now take the first two digits after the decimal, i.e., $04$.

Go to the corresponding row and the find the cell corresponding to the column with the third digit of the decimal i.e., $2$.

The value in that cell is $1102$.

Now go to the corresponding fourth digit in the mean difference table i.e., $7$.

The value is $2$.

Now add $1102$ and $2$.

$\Rightarrow 1102+2=1104$

This should be written with a point such that there are $3$ decimal places.

$\Rightarrow 1.104$

Now this is the value of ${10}^{0.0427}$

Therefore the antilog of $1.0427={10}^1{.10}^{0.0427}={10}^1\times 1.104$

$\Rightarrow 11.04$