Question

Using the antilog table given below, find out the antilog of $3.0419$.

• A. $1099$
• B. $1101$
• C. $11.01$
• D. $109.9$

Answer 1

The correct option is B $1101$

We have to find the antilog of $3.0419$.

$\Rightarrow {10}^{3.0419}$

$\Rightarrow {10}^3{.10}^{0.0419}$

Now take the first two digits after the decimal, i.e., $04$.

Go to the corresponding row and the find the cell corresponding to the column with the third digit of the decimal i.e., $1$.

The value in that cell is $1099$.

Now go to the corresponding fourth digit in the mean difference table i.e., $9$.

The value is $2$.

Now add $1099$ and $2$.

$\Rightarrow 1099+2=1101$

This should be written with a point such that there are $3$ decimal places.

$\Rightarrow 1.101$

Now this is the value of ${10}^{0.0419}$

Therefore the antilog of $3.0419={10}^3{.10}^{0.0419}={10}^3\times 1.101$

$\Rightarrow 1101$