Question

Using the antilog table given below, which of the following is/are not the antilog of $2.0099$ ?

• A. $10.21$
• B. $10.23$
• C. $102.1$
• D. $102.3$

Answer 1

Answer: (A), (B), (C)

$102.1$

We have to find the antilog of $2.0099$.

$\Rightarrow {10}^{2.0099}$

$\Rightarrow {10}^2{.10}^{0.0099}$

Now take the first two digits after the decimal, i.e., $00$.

Go to the corresponding row and the find the cell corresponding to the column with the third digit of the decimal i.e., $9$.

The value in that cell is $1021$.

Now go to the corresponding fourth digit in the mean difference table i.e., $9$.

The value is $2$.

Now add $1021$ and $2$.

$\Rightarrow 1021+2=1023$

This should be written with a point such that there are $3$ decimal places.

$\Rightarrow 1.023$

Now this is the value of ${10}^{0.0099}$

Therefore the antilog of $2.0099={10}^2{.10}^{0.0099}={10}^2\times 1.023$

$\Rightarrow 102.3$