Question

Using the data given find out the strongest reducing agent.
$E_{C{r}_2{O}_7^{2-}/C{r}^{3+}}^o=1.33$V; $E_{C{l}_2/C{l}^{-}}^o=1.36$V
$E_{Mn{O}_4^{-}/M{n}^{2+}}^o=1.51$V; $E_{C{r}^{3+}/Cr}^o=-0.74$V

• A. $C{l}^{-}$
• B. $Cr$
• C. $C{r}^{3+}$
• D. $M{n}^{2+}$

Answer 1

The correct option is B $Cr$

A reducing agent, or reductant, loses electrons and is oxidized in a chemical reaction. A reducing agent is typically in one of its lower possible oxidation states, and is known as the electron donor. A reducing agent is oxidized, because it loses electrons in the redox reaction.

The reduction potentials of the elements are given here. As the reduction potential increases, it tends to undergo reduction easily and acts as oxidising agent.

Lower the value of reduction potential, stronger is the reducing agent i.e., undergoes oxidation most easily.

$Cr\to C{r}^{3+}+3e^{-}$Hence, $Cr$ is the strongest reducing agent.