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Probability

Using the dig...

Question

Using the digits $1, 2, 3, 4, 9$ a five digit number is formed. The probability of having $2$ in the unit's place is

A

\frac{2}{5}

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B

\frac{3}{5}

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C

\frac{4}{5}

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D

\frac{1}{5}

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Solution

The correct option is D $\frac{1}{5}$
Probability of having $2$ in the unit's place is $\frac{4!}{5!} = \frac{1}{5}$

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