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Question

Using the dimensional method derive the relation between the units of force in the SI and CGS system.

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Solution

Let 1 newton(SI) = x dyne(CGS)
Dimensions of forces are [L1M1T2]
[L11M11T21]=x[L12M12T22]
x=(L1L2)1(M1M2)1(T1T2)2
=(mcm)1(kgg)1(ss)2
=102×103=105
1newton=105dyne

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