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Question

Using the figure given below, prove that AR=12 (Perimeter of triangle ABC)

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Solution

Perimeter of ∆ABC = AB+BC+CA
= AB+[BP+CP]+CA
= AB+BQ+CR+CA (Tangents from an external point are equal)
= AQ + AR
= AR + AR (Tangents from an external point are equal)
= 2AR

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