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Question

Using the formula (a+b)2=(a2+2ab+b2, evaluate:
(i) (310)2
(ii) (508)2
(iii) (630)2

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Solution

We know that (a+b)2=(a2+2ab+b2
(i) (310)2=(300+10)2
=(300)2+2×300×10+(10)2
=90000+6000+100=96100
(ii) (508)2=(500+8)2
(500)2+2×500×8+(8)2
250000+8000+64=258064 (iii) (630)2=(600+30)2
=(600)2+2×600×30+(30)2
=360000+36000+900=396900


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