Using the formulae for squaring a binomial, evaluate : $(101)^{2}$

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Solution

We have,
(i) $(101)^{2} = (100 + 1)^{2}$
= $(100)^{2} + 2 \times 100 \times 1 + (1)^{2}$
[Using : $(a + b)^{2} = a^{2} + 2 a b + b^{2}$ ]
= 10000 + 200 + 1
= 10201

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