Question

Using the given figure, find the value of $\angle A$ in degree, if $x=\sqrt{3}y$.

Answer 1

Given, $x=\sqrt{3}y$
Now, $\tan A=\frac{P}{B}=\frac{x}{y}=\sqrt{3}$
$\tan A=\tan 60$
$A={60}^{\circ }$