Using the identity $a^{{log}_{a} n} = n,$ find:
$2^{2 - {log}_{2} 5}$

0.6

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0.8

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0.2

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0.1

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Solution

The correct option is C $0.8$
Given $a^{{log}_{a} n} = n$ .....(1)

Consider,

$2^{2 - {log}_{2} 5} =$ $2^{2} {.2}^{- {log}_{2} 5}$

$= {4.2}^{{log}_{2} 5^{- 1}}$

$= 4 {.5}^{- 1}$ $(b y (1))$

$= \frac{4}{5}$

$2^{2 - {log}_{2} 5} = 0.8$
Ans: 0.8

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