Question

Using the identity $a^{{\log }_{a}n}=n,$ find:

$3^{-\frac{1}{2}{\log }_{3}9}$,

• A. $0.33$
• B. $-0.33$
• C. $0.66$
• D. $-0.66$

Answer 1

Answer: (A)

$0.33$

Given $a^{lo{g}_{a}n}=n$ ....(1)

Consider, $3^{-\frac{1}{2}{\log }_{3}9}$

$=3^{{\log }_3{9}^{-1/2}}$

$=9^{-1/2}$ (by (1))

$=\frac{1}{3}$

$=0.33$

Ans: 0.33