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Question

Using the identity (x+y)2+(xy)2=2(x2+y2)

Compute the value of 42+22


A

z2

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B

10

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C

20

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D

18

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Solution

The correct option is C

20


The given expression is

42+22

=(3+1)2+(31)2

=2(32+12) [(x+y)2+(xy)2=2(x2+y2)]

=2(9+1)

=2×10

=20


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