Question

Using the image above, determine the molecular geometry and hybridization of the $C_1$ atom in a molecule of fructose.

• A. The molecular geometry is tetrahedral and the hybridation is $s{p}^3$.
• B. The molecular geometry is tetrahedral and the hybridation is $s{p}^2$.
• C. The molecular geometry is trigonal planar and the hybridation is $s{p}^3$.
• D. The molecular geometry is trigonal planar and the hybridation is $s{p}^2$.

Answer 1

The correct option is D The molecular geometry is trigonal planar and the hybridation is $s{p}^2$.

(Refer to Image)

As $C_1$ is forming $3$ sigma bond and $1$ pi bond. Thus pi bond is formed by using one of its $p-$orbital. The remaining $p-$ orbitals undergo hybridisation with $S$ and form $3$ hybrid orbitals which participate in sigma bonding. Thus hybridisation of $C_1$ is $s{p}^2$ and the geometry is trigonal planar.