Question

Using the information given in the adjoining figure $\angle$F ${40}^{\circ }$.( Enter 1 if true or 0 otherwise)

Answer 1

In $△$s, ABC and DEF,
$\frac{AB}{DE}=\frac{3.8}{7.6}=\frac{1}{2}$
$\frac{AC}{DF}=\frac{3\sqrt{3}}{6\sqrt{3}}=\frac{1}{2}$
$\frac{BC}{EF}=\frac{6}{12}=\frac{1}{2}$
Since, $\frac{AB}{DE}=\frac{AC}{DF}=\frac{BC}{EF}$
The ratio of corresponding sides is equal.
Hence $△ABC\sim △DEF$