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Question

# Using the information given in the reaction equations below, calculate the heat of formation for 1 mole of carbon monoxide CO. 2C(s)+2O2→2CO2 ΔHrxn=−787kJ 2CO+O2→2CO2 ΔHrxn=−566kJ

A
221kJ/mol
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B
110kJ/mol
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C
110kJ/mol
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D
221kJ/mol
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Solution

## The correct option is A −110kJ/mol2C+2O2→2CO2; Δ1Hrxn=−787kJCO+O2→2CO2; Δ2Hrxn=−566kJ Now, on substracting Equation-1 by 2:2C+O2→2COHence, enthalpy of formation of 2 moles of CO=Δ1Hrxn−Δ2Hrxn=−787−(−566)=−221kJΔHrxn2=−2212=−110.5kJ= Enthalpy of formation of 1 mole of CO

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