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Byju's Answer
Standard VII
Mathematics
Types of Expressions Based on the Number of Terms
Using the met...
Question
Using the method of undetermined coefficients. Show that the expression
(
x
+
1
)
(
x
+
2
)
(
x
+
3
)
(
x
+
4
)
+
1
is the square of a trinomial.
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Solution
(
x
+
1
)
(
x
+
2
)
(
x
+
3
)
(
x
+
4
)
+
1
=
(
x
+
1
)
(
x
+
4
)
(
x
+
2
)
(
x
+
3
)
+
1
=
(
x
2
+
5
x
+
4
)
(
x
2
+
5
x
+
6
)
+
1
Let,
x
2
+
5
x
+
4
=
K
then
=
K
(
K
+
2
)
+
1
=
K
2
+
2
K
+
1
=
(
K
+
1
)
2
=
(
x
2
+
5
x
+
4
+
1
)
2
=
(
x
2
+
5
x
+
5
)
2
Hence proved.
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Similar questions
Q.
The expression
(
x
+
1
)
(
x
+
2
)
(
x
+
3
)
(
x
+
4
)
+
1
is a
Q.
Find the square root of
x
4
−
2
x
3
+
3
x
2
−
2
x
+
1
using the division method
Q.
The square root of
x
4
−
2
x
3
+
3
x
2
−
2
x
+
1
using the division method is equal to
x
2
−
x
+
1
.
Q.
Using division method find the square root of the polynomial:
x
4
+
2
x
3
−
3
x
2
+
2
x
−
1
Q.
Factorise the trinomial
2
x
2
+
7
x
+
6
.
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