Question

Using the prime factor method, find the H.C.F. of
$48,84\text{and}88$

Answer 1

Factor of a number: The number by which the given number can be divided completely. (0.5 marks)
Prime factors of $48=2\times 2\times 2\times 2\times 3$
Prime factors of $84=2\times 2\times 3\times 7$
Prime factors of $88=2\times 2\times 2\times 11$ (1 mark)
$\therefore$ Common prime factors $=2\times 2$
Hence, H.C.F. of $48,84\text{and}88=2\times 2=4$ (0.5 marks)