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Question

Using the prime factor method, find the H.C.F. of
(v) 12,16 and 28

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Solution

(v) Factor of a number: The number by which the given number can be divided completely.
Prime factors of 12=2×2×3
Prime factors of 16=2×2×2×2
Prime factors of 28=2×2×7
Common prime factors =2×2
Hence, H.C.F. of 12, 16 and 28=2×2=4

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