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Question

Using the property ab = akbk , fill in the blanks substituting proper numbers in the following.

(i) 57 = ....28 = 35.... = ....3.5 (ii) 914= 4.5.... = ....42 = ....3.5

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Solution


(i)
28 = 7 × 4, 35 = 5 × 4, 3.5 = 7 × 0.5

Now,

57 = 5×47×4 = 5×77×7 = 5×0.57×0.557 = 2028 = 3549 = 2.53.5
(ii)
4.5 = 9 × 0.5, 42 = 14 × 3, 3.5 = 14 × 0.25

Now,

914=9×0.514×0.5=9×314×3=9×0.2514×0.25914= 4.57 = 2742 = 2.253.5

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