Using the property $\frac{a}{b} = \frac{a k}{b k}$ , fill in the blanks substituting proper numbers in the following. $\frac{5}{7} = \frac{. . .}{28} = \frac{35}{. . .} = \frac{. . .}{3.5}$

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Solution

Given Property $\frac{a}{b} = \frac{a k}{b k}$
$\frac{5}{7} = \frac{- - -}{28} = \frac{35}{- - -} = \frac{- - -}{3.5}$
$\frac{5}{7} = \frac{5 (4)}{7 (4)} = \frac{20}{28}$ as $k = 4$
$\frac{5}{7} = \frac{5 (7)}{7 (7)} = \frac{35}{49}$ as $k = - 7$
$\frac{5}{7} = \frac{5 (0.5)}{7 (0.5)} = \frac{2.5}{3.5}$ as $k = 0.5$
So $\frac{5}{7} = \frac{20}{28} = \frac{35}{49} = \frac{2.5}{3.5}$

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