CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Long Division Method to Divide Two Polynomials

Using the rem...

Question

Using the remainder Theorem, factorise each of the following completely:
(i) $3 x^{3} + 2 x^{2} - 19 x + 6$
(ii) $2 x^{3} + x^{2} - 13 x + 6$
(iii) $3 x^{3} + 2 x^{2} - 23 x - 30$
(iv) $4 x^{3} + 7 x^{2} - 36 x - 63$
(v) $x^{3} + x^{2} - 4 x - 4.$

Open in App

Solution

Suggest Corrections

thumbs-up

6

Similar questions

Q. Using the factor theorem factorise the following polynomial completely

3 x^{3} + 2 x^{2} - 19 x + 6

Question 24
Factorise
(i) $2 x^{3} - 3 x^{2} - 17 x + 30$

(ii) $x^{3} - 6 x^{2} + 11 x - 6$

(iii) $x^{3} + x^{2} - 4 x - 4$

(iv) $3 x^{3} - x^{2} - 3 x + 1$

Q. Evaluate the following:

\begin{matrix} {lim}_{x \to 1} \frac{x^{2} - 3 x + 2}{x^{2} - 4 x + 3} {lim}_{x \to 2} \frac{x^{3} + x^{2} - 12}{x^{3} - x^{2} - x - 2} {lim}_{x \to \sqrt{2}} \frac{x^{2} + x \sqrt{2} - 4}{x^{2} - 3 x \sqrt{2} + 4} {lim}_{x \to 3} \frac{x^{3} - 3 x^{2} - x + 3}{x^{3} - 6 x^{2} + 9 x} \end{matrix}

Question 24
Factorise
(i) $2 x^{3} - 3 x^{2} - 17 x + 30$

(ii) $x^{3} - 6 x^{2} + 11 x - 6$

(iii) $x^{3} + x^{2} - 4 x - 4$

(iv) $3 x^{3} - x^{2} - 3 x + 1$

Consider the system of equations
$x_{1} + 2 x_{2} + 3 x_{3} = 1$
$x_{2} + 2 x_{3} + 3 x_{1} = 2$
$x_{3} + 2 x_{1} + 3 x_{2} = 3$
then

A. $x_{1} = \frac{2}{3}$

B. $x_{1} + x_{2} = \frac{4}{3}$

C. $x_{3} = - \frac{1}{3}$

D. $x_{1} - x_{2} = \frac{1}{3}$

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Long Division Method To Divide Two Polynomials

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Long Division Method to Divide Two Polynomials

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon