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Question

Using the remainder theorem, find the remainder, when p(x) is divided by g(x), where
p(x)=2x3+x215x12,g(x)=x+2

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Solution

p(x)=2x3+x215x12g(x)=x+2

By remainder theorem, when p(x) is divided by ( x+2), then the remainder = p(2).

Putting x = -2 in p(x), we get

p(2)=2(2)3+(2)215(2)12=16+4+3012=6

∴ Remainder = 6Thus, the remainder when p(x) is divided by g(x) is 6.


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