Using the SONAR, sound pulses are emitted at the surface of water. These pulses after being reflected from the bottom of water, are detected. If the time interval from the emission to the detection of sound pulses is $8 s$ , find the depth of water :
(net of sound in water $= 1498 m / s$ )

1498 m

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5992 m

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374.5 m

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18182 m

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Solution

The correct option is D $5992 m$
Let, the depth be $= d$
Total distance travelled by the pulse $= 2 d$
Total time taken $= 8 s$

Velocity = $\frac{d i s t a n c e}{t i m e} = \frac{2 d}{8 s} = \frac{d}{4 s}$

$1498 m / s =$ $\frac{d}{4 s}$

or, $d = 1498 \times 4$

$d = 5992 m$

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Using the SONAR, sound pulses are emitted at the surface of water. These pulses after being reflected from the bottom of water, are detected. If the time interval from the emission to the detection of sound pulses is 8 s, find the depth of water : (net of sound in water =1498m/s)

The correct option is D 5992mLet, the depth be=dTotal distance travelled by the pulse =2dTotal time taken =8sVelocity =distancetime=2d8s=d4s1498m/s= d4sor, d=1498×4 d=5992m

Using the SONAR, sound pulses are emitted at the surface of water. These pulses after being reflected from the bottom of water, are detected. If the time interval from the emission to the detection of sound pulses is $8 s$ , find the depth of water :
(net of sound in water $= 1498 m / s$ )

The correct option is D $5992 m$
Let, the depth be $= d$
Total distance travelled by the pulse $= 2 d$
Total time taken $= 8 s$

Velocity = $\frac{d i s t a n c e}{t i m e} = \frac{2 d}{8 s} = \frac{d}{4 s}$

$1498 m / s =$ $\frac{d}{4 s}$

or, $d = 1498 \times 4$

$d = 5992 m$