Using the standard electrode potentials given in Table 3.1, predict if the reaction between the following is feasible:

(i) Fe³⁺(aq) and I⁻(aq)

(ii) Ag⁺ (aq) and Cu(s)

(iii) Fe³⁺ (aq) and Br⁻(aq)

(iv) Ag(s) and Fe³⁺ (aq)

(v) Br₂(aq) and Fe²⁺(aq).

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Solution

Sincefor the overall reaction is positive, the reaction between Fe³⁺₍_aq₎ and I⁻₍_aq₎ is feasible.

Since for the overall reaction is positive, the reaction between Ag⁺₍_aq₎ and Cu₍_s₎ is feasible.

Since for the overall reaction is negative, the reaction between Fe³⁺₍_aq₎ and Br⁻₍_aq₎ is not feasible.

Since E for the overall reaction is negative, the reaction between Ag₍_s₎ and Fe³⁺₍_aq₎ is not feasible.

Since for the overall reaction is positive, the reaction between Br₂₍_aq₎ and Fe²⁺₍_aq₎ is feasible.

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Similar questions

Using the standard electrode potential valuesl predict if the reaction between the following is feasible :

(i) $F e^{3 +} (a q) a n d I^{-} (a q)$

(ii) $A g^{+} (a q) a n d C u (s)$

(iii) $F e^{3 +} (a q) a n d B r^{-} (a q)$

(iv) $A g (s)$ and $F e^{3 +} (a q)$

(v) $B r_{2} (a q) a n d F e^{2 +} (a q)$

Given standard electrode potentials

$E_{\frac{1}{2} \frac{t_{2}}{1^{-}}}^{\circ} = + 0.541 V E_{(\frac{C u^{2 +}}{C u})}^{\circ} = + 0.34 V E_{(\frac{1}{2} \frac{B r_{2}}{B r^{-}})}^{\circ} = + 1.09 V E_{(\frac{A g^{+}}{A g})}^{\circ} = + 0.80 V E_{(\frac{F e^{3 +}}{F e^{2 +}})}^{\circ} = + 0.77 V$