The correct option is
D 8R1=1Ω,R2=2Ω,quadR3=3Ω
Case-1, when all are in series, Req=6Ω
Case-2, when all are in series, Req=6/11Ω
Case-3,R1 and R2 in series and their resultant is parallel with R3=3/2Ω
Case-4,R1 and R2 in parallel and their resultant is series with R3=11/3Ω
Case-5,R1 and R2 in series and their resultant is parallel with R2=Req=4/3Ω
Case-6,R1 and R2 in series and their resultant is parallel with R2=Req=11/4Ω
Case-7,R2 and R3 in series and their resultant is parallel with R1=Req=5/6Ω
Case-8,R2 and R3 in parallel and their resultant is series with R2=Req=11/5Ω
∴ There are 8 possible ways, we can also find out by using formula 2n where n: no of resistance.