Using trigonometric tables, find the value of $c o s 37^{\circ} 20^{'}$ .

0.7951

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0.8951

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0.7645

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0.6445

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Solution

The correct option is A
0.7951

We have $c o s 37^{\circ} 20^{'} = 37^{\circ} + 18^{'} + 2^{'}$ .

From the trigonometric table, we have

$c o s 37^{\circ} 18^{'} = 0.7955$

Mean difference for $2^{'} = 0.0004$ [To be subtracted]

So, $c o s 37^{\circ} 20 = 0.7951$

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