Question

Using trigonometric tables, find the value of $cos(85.2{)}^{\circ }$.

• A. 0.0837
• B. 0.825
• C. 0.0737
• D. 0.0636

Answer 1

The correct option is A

0.0837

We know that

$(0.1{)}^{\circ }=6^{\prime }$

$\Rightarrow$ $(0.2{)}^{\circ }={12}^{\prime }$

$\Rightarrow$ $(85.2{)}^{\circ }={85}^{\circ }{12}^{\prime }$

$\Rightarrow$ $cos(85.2{)}^{\circ }=cos((85.2{)}^{\circ }{12}^{\prime }=0.0837$