Using trigonometric tables, find the value of $s i n (25.7)^{\circ}$ .

0.0837

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0.4834

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0.4337

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0.0767

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Solution

The correct option is C
0.4337

We know that

$(0.1)^{\circ} = 6^{'}$

$\Rightarrow$ $(0.7)^{\circ} = 42^{'}$

$\Rightarrow$ $(25.7)^{\circ} = 25^{\circ} 42^{'}$

$\Rightarrow$ $s i n (25.7)^{\circ} = s i n (25)^{\circ} 42^{'} = 0.4337$

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Using trigonometric tables, find the value of sin(25.7)∘.

The correct option is C 0.4337 We know that (0.1)∘ =6′ ⇒ (0.7)∘=42′ ⇒ (25.7)∘=25∘42′ ⇒ sin(25.7)∘=sin(25)∘42′=0.4337

Using trigonometric tables, find the value of $s i n (25.7)^{\circ}$ .

The correct option is C
0.4337

We know that

$(0.1)^{\circ} = 6^{'}$

$\Rightarrow$ $(0.7)^{\circ} = 42^{'}$

$\Rightarrow$ $(25.7)^{\circ} = 25^{\circ} 42^{'}$

$\Rightarrow$ $s i n (25.7)^{\circ} = s i n (25)^{\circ} 42^{'} = 0.4337$