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Question

Using van der Waal's equation, calculate the constant 'a' (in atm litre2 mol2), when two moles of a gas confined in a four-litre flask exerts a pressure of 11.0 atmosphere at a temperature of 300 K. The value of 'b' is 0.05 litre mol1.
Write integer part only.

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Solution

van der Waal's equation for n mole of gas is:

[P+n2aV2][Vnb]=nRT

Given,

V=4 litre;

P=11.0 atm,

T=300 K; b=0.05 litre mol1,

n=2

Thus, [11+22a42][42×0.05]=2×0.0821×300

a=6.46 atm litre2 mol2

and integer part of this is 6.

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