Question

Using Van der Waals equation, $[P+\frac{a}{V^2}](V-b)=RT$, at high pressure, the Van der Waals equation gets reduced to :

• A. $[P+\frac{a}{V^2}]V=RT$
• B. $P(V-b)=RT$
• C. $PV=RT$
• D. $[P+\frac{a}{V^2}](V-b)=RT$

Answer 1

Answer: (B)

$P(V-b)=RT$

At higher pressure, the pressure correction for $1$ mole of gas is negligible.

$\therefore \frac{a}{V^2}=0$

or $(P+0)(V-b)=RT$ or, $P(V_m-b)=RT$

Hence, option $\left(B\right)$ is correct.