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(x±a)(x±b) = x²±(a+b)x+ab.

Using x+a x...

Question

Using $(x + a) (x + b) = x^{2} + (a + b) x + a b,$ find
$103 \times 98$

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Solution

$103 \times 98 = (100 + 3) \times (100 - (- 2))$
$= 100^{2} + 120 (3 - 2) + 3 (- 2)$
$= 1000 + 100 - 6$
$= 10094$

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(x±a)(x±b) = x²±(a+b)x+ab.

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