Question

$v_1$ is the frequency of the series limit of Lyman series, $v_2$ is the frequency of the first line of Lyman series and $v_3$ is the frequency of the series limit of the Balmer series. Then

• A. $v_1-v_2=v_3$
• B. $v_1=v_2-v_3$
• C. $\frac{1}{v_2}=\frac{1}{v_1}+\frac{1}{v_2}$
• D. $\frac{1}{v_1}=\frac{1}{v_2}+\frac{1}{v_3}$

Answer 1

The correct option is A $v_1-v_2=v_3$

$\nu =C[\frac{1}{n^2}-\frac{1}{m^2}]$

For series limit of Lyman series

$n=1,m=\infty$

${\nu }_1=C$

For first limit of Lyman series

$n=1,m=2$

${\nu }_2=\frac{3C}{4}$

For series limit of Balman series

$n=2,m=\infty$

${\nu }_3=\frac{C}{4}$

${\nu }_1-{\nu }_2={\nu }_3$