Question 81 (v)
Add :
2p4−3p3+p2−5p+7,−3p4−7p3−3p2−p−12
We have,
(2p4−3p3+p2−5p+7)+(−3p4−7p3−3p2−p−12)
=2p4−3p3+p2−5p+7−3p4−7p3−3p2−p−12
=(2p4−3p4)+(−3p3−7p3)+(p2−3p2)+(−5p−p)+(7−12)
[grouping like terms]
=−p4−10p3−2p2−6p−5