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Factorisation Using Algebraic Identities

v Factorise a...

Question

Question 4(v)
Factorise
$a^{4} - 2 a^{2} b^{2} + b^{4}$

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Solution

$a^{4} - 2 a^{2} b^{2} + b^{4} = (a^{2})^{2} - 2 (a^{2}) (b^{2}) + (b^{2})^{2} = (a^{2} - b^{2})^{2} = [(a - b) (a + b)]^{2} = (a - b)^{2} (a + b)^{2}$

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Similar questions

Q. Question 1(viii)
Factorise the following expressions

a^{4} + 2 a^{2} b^{2} + b^{4}

a^{4} + 2 a^{2} b^{2} + b^{4}

a^{4} + 2 a^{2} b^{2} + b^{4}

Q. Which of the following represents the factorisation of the expression

a^{4} + 2 a^{2} b^{2} + b^{4} ?

Q. Question 4(v)
Factorise

a^{4} - 2 a^{2} b^{2} + b^{4}

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Factorisation Using Algebraic Identities

Standard VIII Mathematics

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