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Question 1 (v)
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.

t215

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Solution

t215

Comparing given polynomial with the general form ax2+bx+c,

We get, a = 1, b = 0 and c = -15

We have, t2 - 0.t - 15

=(t15)(t+15)

The value of t2 - 15 is zero when t - 15 = 0 or t + 15 = 0, i.e., when t = 15 or t = -15

Therefore, the zeroes of t2 - 15 are 15 and -15
Sum of zeroes = 15 + -15=0=01=(Coefficient of t)Coefficient of t2
Product of zeroes = (15)(15)=15=151=Constant termCoefficient of t2


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