(v)
For this A.P.,a2=38a6=−22We know that, an=a+(n−1)da2=a+(2−1)d38=a+d……(i)a6=a+(6−1)d−22=a+5d……(ii)On subtracting (i) from (ii), we get−22−38=4d−60=4dd=−15a=a2−d=38−(−15)=53a3=a+2d=53+2(−15)=23a4=a+3d=53+3(−15)=8a5=a+4d=53+4(−15)=−7
Therefore, the missing terms are 53, 23, 8, and −7 respectively.