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Question

Question 3 (v)
In the following APs, find the missing term in the boxes.

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Solution

(v)
For this A.P.,a2=38a6=22We know that, an=a+(n1)da2=a+(21)d38=a+d(i)a6=a+(61)d22=a+5d(ii)On subtracting (i) from (ii), we get2238=4d60=4dd=15a=a2d=38(15)=53a3=a+2d=53+2(15)=23a4=a+3d=53+3(15)=8a5=a+4d=53+4(15)=7
Therefore, the missing terms are 53, 23, 8, and −7 respectively.

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